3x^2+75x-25000=0

Solution for 3x^2+75x-25000=0 equation:

3x^2+75x-25000=0

a = 3; b = 75; c = -25000;
Δ = b2-4ac
Δ = 752-4·3·(-25000)
Δ = 305625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{305625}=\sqrt{625*489}=\sqrt{625}*\sqrt{489}=25\sqrt{489}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(75)-25\sqrt{489}}{2*3}=\frac{-75-25\sqrt{489}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(75)+25\sqrt{489}}{2*3}=\frac{-75+25\sqrt{489}}{6}
$